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प्रश्न
Prove the following identity :
`tan^2A - sin^2A = tan^2A.sin^2A`
उत्तर
LHS = `tan^2A - sin^2A`
= `sin^2A/cos^2A - sin^2A = (sin^2A(1 - cos^2A))/cos^2A`
= `sin^2A/cos^2A.sin^2A = tan^2A.sin^2A` = RHS
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