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प्रश्न
Prove that `(sin^2theta)/(cos theta) + cos theta` = sec θ
उत्तर
L.H.S = `(sin^2theta)/(cos theta) + cos theta`
= `(sin^2theta + cos^2theta)/costheta`
= `1/costheta` ......[∵ sin2θ + cos2θ = 1]
= sec θ
= R.H.S
∴ `(sin^2theta)/(cos theta) + cos theta` = sec θ
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