मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

Prove the following identities. sin3A+cos3AsinA+cosA+sin3A-cos3AsinA-cosA = 2 - Mathematics

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प्रश्न

Prove the following identities.

`(sin^3"A" + cos^3"A")/(sin"A" + cos"A") + (sin^3"A" - cos^3"A")/(sin"A" - cos"A")` = 2

बेरीज

उत्तर

`(sin^3"A" + cos^3"A")/(sin"A" + cos"A") + (sin^3"A" - cos^3"A")/(sin"A" - cos"A")` = 2

L.H.S = `(sin^3"A" + cos^3"A")/(sin"A" + cos"A") + (sin^3"A" - cos^3"A")/(sin"A" - cos"A")`

= `((sin"A" + cos"A")(sin^2"A" - sin"A"cos"A" + cos^2"A"))/((sin"A" + cos"A")) + ((sin"A" - cos"A")(sin^2"A" + sin"A"cos"A" + cos^2"A"))/((sin"A" - cos"A"))`

= (sin2 A + cos2 A) − sin A cos A + (sin2 A + cos2 A) + sin A cos A

= 1 + 1

= 2

L.H.S = R.H.S

∴`(sin^3"A" + cos^3"A")/(sin"A" + cos"A") + (sin^3"A" - cos^3"A")/(sin"A" - cos"A")` = 2

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पाठ 6: Trigonometry - Exercise 6.1 [पृष्ठ २५०]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 6 Trigonometry
Exercise 6.1 | Q 6. (ii) | पृष्ठ २५०
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