Advertisements
Advertisements
प्रश्न
The area of the region bounded by the circle x2 + y2 = 1 is ______.
पर्याय
2π sq.units
π sq.units
3π sq.units
4π sq.units
उत्तर
The area of the region bounded by the circle x2 + y2 = 1 is π sq.units.
Explanation:
Given equation of circle is x2 + y2 = 1
⇒ y = `sqrt(1 - x^2)`
Since the circle is symmetrical about the axes.
∴ Required area = `4 xx int_0^1 sqrt(1 - x^2) "d"x`
= `4[x/2 sqrt(1 - x^2) + 1/2 sin^-1 x]_0^1`
= `4[0 + 1/2 sin^-1 (1) - 0 - 0]`
= `4 xx 1/2 xx pi/2`
= π sq.units
APPEARS IN
संबंधित प्रश्न
Find the area of the region bounded by the curve y = sinx, the lines x=-π/2 , x=π/2 and X-axis
Find the area lying above the x-axis and under the parabola y = 4x − x2.
Draw a rough sketch to indicate the region bounded between the curve y2 = 4x and the line x = 3. Also, find the area of this region.
Make a rough sketch of the graph of the function y = 4 − x2, 0 ≤ x ≤ 2 and determine the area enclosed by the curve, the x-axis and the lines x = 0 and x = 2.
Sketch the graph of y = \[\sqrt{x + 1}\] in [0, 4] and determine the area of the region enclosed by the curve, the x-axis and the lines x = 0, x = 4.
Find the area under the curve y = \[\sqrt{6x + 4}\] above x-axis from x = 0 to x = 2. Draw a sketch of curve also.
Find the area of the region bounded by x2 = 4ay and its latusrectum.
Draw a rough sketch and find the area of the region bounded by the two parabolas y2 = 4x and x2 = 4y by using methods of integration.
Make a sketch of the region {(x, y) : 0 ≤ y ≤ x2 + 3; 0 ≤ y ≤ 2x + 3; 0 ≤ x ≤ 3} and find its area using integration.
Find the area of the region between the parabola x = 4y − y2 and the line x = 2y − 3.
The area included between the parabolas y2 = 4x and x2 = 4y is (in square units)
The area bounded by y = 2 − x2 and x + y = 0 is _________ .
The area bounded by the parabola y2 = 8x, the x-axis and the latusrectum is ___________ .
Area lying in first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2, is
The area enclosed by the ellipse `x^2/"a"^2 + y^2/"b"^2` = 1 is equal to ______.
Find the area of the region included between y2 = 9x and y = x
Compute the area bounded by the lines x + 2y = 2, y – x = 1 and 2x + y = 7.
Area of the region bounded by the curve `y^2 = 4x`, `y`-axis and the line `y` = 3 is:
Find the area of the region bounded by curve 4x2 = y and the line y = 8x + 12, using integration.
Find the area of the region enclosed by the curves y2 = x, x = `1/4`, y = 0 and x = 1, using integration.
Let f : [–2, 3] `rightarrow` [0, ∞) be a continuous function such that f(1 – x) = f(x) for all x ∈ [–2, 3]. If R1 is the numerical value of the area of the region bounded by y = f(x), x = –2, x = 3 and the axis of x and R2 = `int_-2^3 xf(x)dx`, then ______.
Let g(x) = cosx2, f(x) = `sqrt(x)`, and α, β (α < β) be the roots of the quadratic equation 18x2 – 9πx + π2 = 0. Then the area (in sq. units) bounded by the curve y = (gof)(x) and the lines x = α, x = β and y = 0, is ______.
Using integration, find the area of the region bounded by y = mx (m > 0), x = 1, x = 2 and the X-axis.
Using integration, find the area bounded by the curve y2 = 4ax and the line x = a.
Sketch the region enclosed bounded by the curve, y = x |x| and the ordinates x = −1 and x = 1.
Hence find the area bounded by the curve, y = x |x| and the coordinates x = −1 and x = 1.