Advertisements
Advertisements
प्रश्न
The value of x − yx-y when x = 2 and y = −2 is
पर्याय
18
-18
14
-14
उत्तर
Given `x- y ^(x-y)`
Here `x = 2, =-2`
By substituting in `x- y ^(x-y)` we get
`x-y^(x-y) = 2-(-2)^(2-(-2))`
`= 2-(-2)^(2 +2))`
`= 2-(-2)^4`
= -14
The value of `x- y ^(x-y)`is – 14
Hence the correct choice is d .
APPEARS IN
संबंधित प्रश्न
Prove that:
`(x^a/x^b)^cxx(x^b/x^c)^axx(x^c/x^a)^b=1`
Simplify:
`((5^-1xx7^2)/(5^2xx7^-4))^(7/2)xx((5^-2xx7^3)/(5^3xx7^-5))^(-5/2)`
Prove that:
`sqrt(3xx5^-3)divroot3(3^-1)sqrt5xxroot6(3xx5^6)=3/5`
Find the value of x in the following:
`2^(5x)div2x=root5(2^20)`
Find the value of x in the following:
`5^(2x+3)=1`
If `2^x xx3^yxx5^z=2160,` find x, y and z. Hence, compute the value of `3^x xx2^-yxx5^-z.`
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
The value of \[\left\{ 8^{- 4/3} \div 2^{- 2} \right\}^{1/2}\] is
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
Find:-
`16^(3/4)`
