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Question
Calculate the binding energy of an alpha particle given its mass to be 4.00151 u.
Solution
Data: M = 4.00151 u, mp = 1.00728 u, mn = 1.00866 u, 1 u = 931.5 MeV/c2
The binding energy of an alpha particle =
(Zmp + Nmn - M)c2
= (2mp + 2mn - M)c2
= [(2)(1.00728 u) + 2(1.00866 u) - 4.00151 u]c2
= (2.01456 + 2.01732 - 4.00151)(931.5) MeV
= 28.289655 MeV
= 28.289655 × 106 eV × 1.602 × 10-10 J
= 4.532002731 × 10-12 J
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