Advertisements
Advertisements
Question
Choose the correct alternative:
`int_0^"a" 3x^5 "d"x` = 8, then a =
Options
2
0
`8/3`
a
Solution
2
APPEARS IN
RELATED QUESTIONS
Show that: `int _0^(pi/4) log (1 + tanx) dx = pi/8 log2`
Evaluate : `int_0^(pi/4) sec^4x*dx`
Evaluate the following:
`int_0^(pi/2) log(tanx)dx`
Evaluate the following : `int_(-3)^(3) x^3/(9 - x^2)*dx`
Choose the correct option from the given alternatives :
If `dx/(sqrt(1 + x) - sqrt(x)) = k/(3)`, then k is equal to
Choose the correct alternative :
If `int_0^"a" 3x^2*dx` = 8, then a = ?
Fill in the blank : If `int_0^"a" 3x^2*dx` = 8, then a = _______
Solve the following : `int_2^3 x/(x^2 - 1)*dx`
Solve the following : `int_2^4 x/(x^2 + 1)*dx`
Evaluate `int_0^1 1/(sqrt(1 + x) + sqrt(x)) "d"x`
Evaluate the following definite intergral:
`int_-2^3 1/(x+5) dx`
Evaluate the following definite integral:
`int_1^3 log x dx`
Evaluate the following definite integral:
`int_4^9 1/sqrtx dx`
`int_0^1 1/(2x + 5)dx` = ______
Evaluate the following definite intergral:
`int_4^9 1/sqrtxdx`
Solve the following.
`int_0^1 e^(x^2) x^3 dx`
Evaluate the following definite intergral:
`int_1^2(3x)/(9x^2-1).dx`
Evaluate the following definite integrals: `int_1^2 (3x)/((9x^2 - 1))*dx`
Evaluate the following definite integral:
`int_1^2 (3x)/((9x^2 - 1))*dx`
Solve the following.
`int_1^3 x^2 logxdx`
