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Find dxdy in the following. x2 + xy + y2 = 100 - Mathematics

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Question

Find `dx/dy` in the following.

x2 + xy + y2 = 100

Sum

Solution

Since, x2 + xy + y2 = 100

Differentiating both sides with respect to x,

`=> d/dx (x^2) + {x dy/dx + y d/dx (x)} + d/dx (y^2) = d/dx (100)`

`=> 2x = x dy/dx + y xx 1 + 2y dy/dx = 0`

`=> 2x + x dy/dx + y + 2y dy/dx = 0`

`=> x dy/dx + 2y dy/dx = -2 x - 1`

`=> dy/dx (x + 2y) = - (2x - y)`

`dy/dx = (- 2x + y)/(x + 2y)`

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Chapter 5: Continuity and Differentiability - Exercise 5.3 [Page 169]

APPEARS IN

NCERT Mathematics [English] Class 12
Chapter 5 Continuity and Differentiability
Exercise 5.3 | Q 5 | Page 169

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