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Question
Find the value of `tan^-1 [2 cos (2 sin^-1 1/2)] + tan^-1 1`.
Solution
`tan^-1 [2 cos (2 xx π/6)] + tan^-1 (1)`
= `tan^-1 (2 cos π/3) + π/4`
= `tan^-1 (2 xx 1/2) + π/4`
= `tan^-1 (1) + π/4`
= `π/4 + π/4`
= `π/2`
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