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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Find the value of tan 7π12 - Mathematics

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Question

Find the value of tan `(7pi)/12`

Sum

Solution

tan `(7pi)/12 = 7 xx 180/12`

= 7 × 15°

= 105°

tan(105°) = tan(90° + 15°)

= – cot 15°

= `- 1/tan15^circ`

= `- 1/(tan(45^circ - 30^circ))`

= `- 1/((tan45^circ - tan30^circ)/(1 + tan45^circ* tan30^circ))`

= `- (1 + tan45^circ*  tan30^circ)/(tan45^circ - tan30^circ)`

= `- (1 + (1) * (1/sqrt(3)))/(1 - 1/sqrt(3))`

= `- ((sqrt(3)+  1)/sqrt(3))/((sqrt(3) - 1)/sqrt(3))`

= `- (sqrt(3) + 1)/(sqrt(3) - 1)`

= `- (sqrt(3) + 1)/(sqrt(3) - 1) xx - (sqrt(3) + 1)/(sqrt(3) + 1)`

= `- ((sqrt(3) + 1)^2)/((sqrt(3))^2 - 1^2)`

= `- ((3 + 2sqrt(3) + 1))/(3 - 1)`

tan(105°) = `- (4 + 2sqrt(3))/2`

= `- (2 + sqrt(3))`

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Trigonometric Functions and Their Properties
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Chapter 3: Trigonometry - Exercise 3.4 [Page 109]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 3 Trigonometry
Exercise 3.4 | Q 5. (iii) | Page 109

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