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Question
Find the value of a if `[[a-b,2a+c],[2a-b,3c+d]]=[[-1,5],[0,13]]`
Solution
`[[a-b,2a+c],[2a-b,3c+d]]=[[-1,5],[0,13]]`
a-b=-1,2a+c=5,2a-b=0,3c+d=13
using a-b=-1 and 2a-b=0 we get a=1
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