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Question
Given P01(M-E) = 120, `sum"p"_1"q"_1` = 300, `sum"p"_0"q"_0` = 120, `sum"p"_0"q"_1` = 320, Find P01(L)
Solution
Given, P01(M-E) = 120, `sum"p"_1"q"_1` = 300, `sum"p"_0"q"_0` = 120, `sum"p"_0"q"_1` = 320
P01(M-E) = `(sum"p"_1"q"_0 + sum"p"_1"q"_1)/(sum"p"_0"q"_0 + sum"p"_0"q"_1) xx 100`
∴ 120 = `(sum"p"_1"q"_0 + 300)/(120 + 130) xx 100`
∴ 120 = `(sum"p"_1"q"_0 + 300)/440 xx 100`
∴ `sum"p"_1"q"_0 + 300 = (120 xx 440)/100`
∴ `sum"p"_1"q"_0 + 300` = 528
∴ `sum"p"_1"q"_0` = 528 – 300
∴ `sum"p"_1"q"_0` = 228
Laspeyre’s Price Index Number:
P01(L) = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100`
= `228/120 xx 100`
= 190
RELATED QUESTIONS
If P01(L) = 90 and P01(P) = 40, find P01(D – B) and P01(F).
If Laspeyre's Price Index Number is four times Paasche's Price Index Number, then find the relation between Dorbish-Bowley's and Fisher's Price Index Numbers.
If Dorbish-Bowley's and Fisher's Price Index Numbers are 5 and 4, respectively, then find Laspeyre's and Paasche's Price Index Numbers.
Laspeyre’s Price Index Number is given by ______.
Paasche’s Price Index Number is given by ______
Dorbish-Bowley’s Price Index Number is given by ______.
Laspeyre’s Price Index Number is given by _______.
State whether the following is True or False :
`sqrt(("p"_1"q"_0)/(sum"p"_0"q"_0)) xx sqrt((sum"p"_1"q"_1)/(sum"p"_0"q"_1)) xx 100` is Fisher’s Price Index Number.
Solve the following problem :
Calculate Dorbish-Bowley’s Price Index Number for the following data.
Commodity | Base Year | Current Year | ||
Price p0 |
Quantity q0 |
Price p1 |
Quantity q1 |
|
I | 8 | 30 | 11 | 28 |
II | 9 | 25 | 12 | 22 |
III | 10 | 15 | 13 | 11 |
Solve the following problem :
Calculate Marshall-Edgeworth’s Price Index Number for the following data.
Commodity | Base Year | Current Year | ||
Price p0 |
Quantity q0 |
Price p1 |
Quantity q1 |
|
X | 12 | 35 | 15 | 25 |
Y | 29 | 50 | 30 | 70 |
Solve the following problem :
Calculate Walsh’s Price Index Number for the following data.
Commodity | Base year | Current year | ||
Price p0 |
Quantity q0 |
Price p1 |
Quantity q1 |
|
I | 8 | 30 | 12 | 25 |
II | 10 | 42 | 20 | 16 |
Solve the following problem :
Given that Laspeyre’s and Paasche’s Price Index Numbers are 25 and 16 respectively, find Dorbish-Bowley’s and Fisher’s Price Index Number.
Solve the following problem :
Given that `sum "p"_0"q"_0 = 130, sum "p"_1"q"_1 = 140, sum "p"_0"q"_1 = 160, and sum "p"_1"q"_0 = 200`, find Laspeyre’s, Paasche’s, Dorbish-Bowley’s, and Marshall-Edgeworth’s Price Index Numbers.
Choose the correct alternative:
Price Index Number by using Weighted Aggregate Method is given by
Choose the correct alternative:
Fisher’s Price Index Number is
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Marshall-Edgeworth's Price Index Number is given by ______
The average of Laspeyre’s and Paasche’s Price Index Numbers is called ______ Price Index Number
State whether the following statement is True or False:
`(sum"p"_0sqrt("q"_0 + "q"_1))/(sum"p"_1sqrt("q"_0 + "q"_1)) xx 100` is Marshall-Edgeworth Price Index Number
If Laspeyre’s and Paasche’s Price Index Numbers are 50 and 72 respectively, find Dorbish-Bowley’s and Fisher’s Price Index Numbers
If `sum"p"_0"q"_0` = 150, `sum"p"_0"q"_1` = 250, `sum"p"_1"q"_1` = 375 and P01(L) = 140. Find P01(M-E)
State whether the following statement is true or false:
Dorbish-Bowley's Price Index Number is the square root of the product of Laspeyre's and Paasche's Index Numbers.
Laspeyre’s Price Index Number uses current year’s quantities as weights.
Calculate Marshall – Edgeworth’s price index number for the following data:
Commodity | Base year | Current year | ||
Price | Quantity | Price | Quantity | |
P | 12 | 20 | 18 | 24 |
Q | 14 | 12 | 21 | 16 |
R | 8 | 10 | 12 | 18 |
S | 16 | 15 | 20 | 25 |
If ∑ p0q0 = 120, ∑ p0q1 = 160, ∑ p1q1 = 140, ∑ p1qo = 200, find Laspeyre’s, Paasche’s, Dorbish-Bowley’s and Marshall-Edgeworth’s Price Index Numbers.
In the following table, Laspeyre's and Paasche's Price Index Numbers are equal. Complete the following activity to find x :
Commodity | Base Year | Current year | ||
Price | Quantity | Price | Quantity | |
A | 2 | 10 | 2 | 5 |
B | 2 | 5 | x | 2 |
Solution: P01(L) = P01(P)
`(sum "p"_1"q"_0)/(sum "p"_0"q"_0) xx 100 = square/(sum "p"_0"q"_1) xx 100`
`(20 + 5x)/square xx 100 = square/14 xx 100`
∴ x = `square`