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How many A.P.'s with 10 terms are there whose first term is in the set {1, 2, 3} and whose common difference is in the set {1, 2, 3, 4, 5}? - Mathematics

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Question

How many A.P.'s with 10 terms are there whose first term is in the set {1, 2, 3} and whose common difference is in the set {1, 2, 3, 4, 5}?

Solution

Number of ways of selecting the first term from the set {1, 2, 3} = 3
Corresponding to each of the selected first terms, the number of ways of selecting the common difference  from the set {1, 2, 3, 4, 5} = 5
∴ Total number of AP's that can be formed = 3\[\times\]5 = 15

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Chapter 16: Permutations - Exercise 16.2 [Page 15]

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RD Sharma Mathematics [English] Class 11
Chapter 16 Permutations
Exercise 16.2 | Q 14 | Page 15

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