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Question
In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?
Solution
3 boys and 3 girls are to be selected from 5 boys and 4 girls.
∴ Required ways = \[{}^5 C_3 \times^4 C_3 = \frac{5}{3} \times \frac{4}{2} \times \frac{3}{1} \times \frac{4}{3} \times \frac{3}{2} \times \frac{2}{1} = 40\]
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