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Question
In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: sin P
Solution
ΔQSP is a right-angled triangle.
∴ PQ2 = QS2 + PS2
= 32 + 42
= 9 + 16
= 25
⇒ PQ = 5cm
sin P
= `"QS"/"PQ"`
= `(3)/(5)`.
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