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Prove that the function f given by f(x)=|x-1|,x ∈R is not differentiable at x = 1. - Mathematics

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Question

Prove that the function f given by  `f(x) = |x - 1|, x  in R`  is not differentiable at x = 1.

Sum

Solution

Any function will not be differentiable if the left hand limit and the right hand limit are not equal.

f(x) = `abs (x - 1), x in R`

f(x) = (x - 1), if x - 1 > 0

= - (x - 1), if x -1 < 0

At x = 1

f(1) = 1 - 1 = 0

left side limit =

`lim_(h -> 0^-) (f(1 - h) - f(1))/ -h`

= `lim_(h -> 0^-) (1 - (1 - h) - 0)/ (- h)`

= `lim_(h -> 0^-) (+ h)/(- h)`

= - 1

Right side limit =

= `lim_(h -> 0^+) (f(1 + h) - f(1))/h`

= `lim_(h -> 0^+) ((1 + h) - 1 - 0)/ h`

= `lim_(h -> 0^+) h/h`

= 1

Left side limit and right side limit are not equal.

Hence, f(x) is not differentiable at x = 1.

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Chapter 5: Continuity and Differentiability - Exercise 5.2 [Page 166]

APPEARS IN

NCERT Mathematics [English] Class 12
Chapter 5 Continuity and Differentiability
Exercise 5.2 | Q 10 | Page 166

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