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Question
Solve the following equations for x:
`3^(2x+4)+1=2.3^(x+2)`
Solution
`3^(2x+4)+1=2.3^(x+2)`
`rArr(3^(x+2))^2-2.3^(x+2)+1=0`
`rArr(3^(x+2)-1)^2=0`
`rArr3^(x+2)-1=0`
`rArr3^(x+2)=1`
`rArr3^(x+2)=3^0`
⇒ x + 2 = 0
⇒ x = -2
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