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Question
The circumference of a circle is measured as 28 cm with an error of 0.01 cm. The percentage error in the area is
Options
\[\frac{1}{14}\]
0.01
\[\frac{1}{7}\]
none of these
Solution
\[\frac{1}{14}\]
Let x be the radius of the circle and y be its circumference.
\[x = 28 cm\]
\[ ∆ x = 0 . 01 cm\]
\[x = 2\pi r\]
\[y = \pi r^2 = \pi \times \frac{x^2}{4 \pi^2} = \frac{x^2}{4\pi}\]
\[ \Rightarrow \frac{dy}{dx} = \frac{x}{2\pi}\]
\[ \Rightarrow \frac{∆ y}{y} = \frac{x}{2\pi y}dx = \frac{2}{x} \times 0 . 01\]
\[ \Rightarrow \frac{∆ y}{y} \times 100 = \frac{2}{x} = \frac{1}{14}\]
\[\text { Hence, the percentage error in the area is } \frac{1}{14} .\]
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