English

Using Differentials, Find the Approximate Value of the Following up to 3 Places of Decimal `Sqrt(25.3)` - Mathematics

Advertisements
Advertisements

Question

Using differentials, find the approximate value of the following up to 3 places of decimal

`sqrt(25.3)`

Solution

`sqrt(25.3)`

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Application of Derivatives - Exercise 6.4 [Page 216]

APPEARS IN

NCERT Mathematics [English] Class 12
Chapter 6 Application of Derivatives
Exercise 6.4 | Q 1.1 | Page 216

Video TutorialsVIEW ALL [2]

RELATED QUESTIONS

Find the approximate value of cos (60° 30').

(Given: 1° = 0.0175c, sin 60° = 0.8660)


Using differentials, find the approximate value of the following up to 3 places of decimal

`(255)^(1/4)`


Using differentials, find the approximate value of the following up to 3 places of decimal

`(82)^(1/4)`


Using differentials, find the approximate value of the following up to 3 places of decimal

`(26.57)^(1/3)`


The approximate change in the volume of a cube of side x metres caused by increasing the side by 3% is

A. 0.06 x3 m3 

B. 0.6 x3 m3

C. 0.09 x3 m3

D. 0.9 x3 m3


Show that the function given by `f(x) = (log x)/x` has maximum at x = e.


The normal at the point (1, 1) on the curve 2y + x2 = 3 is

(A) x + y = 0

(B) x − = 0

(C) x + y + 1 = 0

(D) − y = 1


The radius of a sphere shrinks from 10 to 9.8 cm. Find approximately the decrease in its volume ?


If there is an error of 0.1% in the measurement of the radius of a sphere, find approximately the percentage error in the calculation of the volume of the sphere ?


Using differential, find the approximate value of the following: \[\left( 0 . 007 \right)^\frac{1}{3}\]


Using differential, find the approximate value of the \[\left( 255 \right)^\frac{1}{4}\] ?


Using differential, find the approximate value of the loge 4.04, it being given that log104 = 0.6021 and log10e = 0.4343 ?


Using differential, find the approximate value of the loge 10.02, it being given that loge10 = 2.3026 ?


Using differentials, find the approximate values of the cos 61°, it being given that sin60° = 0.86603 and 1° = 0.01745 radian ?


Using differential, find the approximate value of the \[\frac{1}{\sqrt{25 . 1}}\] ?


Using differential, find the approximate value of the \[\sin\left( \frac{22}{14} \right)\] ?


Using differential, find the approximate value of the \[\cos\left( \frac{11\pi}{36} \right)\] ?


Using differential, find the approximate value of the \[\left( 29 \right)^\frac{1}{3}\] ?


Using differential, find the approximate value of the \[\sqrt{49 . 5}\] ?


Using differential, find the approximate value of the \[\left( 3 . 968 \right)^\frac{3}{2}\] ?


Find the approximate value of log10 1005, given that log10 e = 0.4343 ?


If the radius of a sphere is measured as 9 cm with an error of 0.03 m, find the approximate error in calculating its surface area ?


If y = loge x, then find ∆y when x = 3 and ∆x = 0.03 ?


If the relative error in measuring the radius of a circular plane is α, find the relative error in measuring its area ?


The circumference of a circle is measured as 28 cm with an error of 0.01 cm. The percentage error in the area is

 


For the function y = x2, if x = 10 and ∆x = 0.1. Find ∆y.


Find the approximate values of : `root(3)(28)`


Find the approximate values of (4.01)3 


Find the approximate values of : tan–1 (1.001)


Find the approximate values of : e0.995, given that e = 2.7183.


Find the approximate values of : e2.1, given that e2 = 7.389


Find the approximate values of : 32.01, given that log 3 = 1.0986


Solve the following : Find the approximate value of cos–1 (0.51), given π = 3.1416, `(2)/sqrt(3)` = 1.1547.


If y = x4 – 10 and if x changes from 2 to 1.99, what is the change in y ______.


If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, then find the approximating error in calculating its volume.


Find the approximate value of f(3.02), where f(x) = 3x2 + 5x + 3


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×