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Question
If the ratio of base radius and height of a cone is 1 : 2 and percentage error in radius is λ %, then the error in its volume is
Options
λ %
2 λ %
3 λ %
none of these
Solution
3 λ %
Let the radius of the cone be x, the height be 2x and the volume be y.
\[\frac{∆ x}{x} = \lambda \] %
\[ \Rightarrow y = \frac{1}{3}\pi x^2 \times 2x = \frac{2}{3}\pi x^3 \]
\[ \Rightarrow \frac{dy}{dx} = 2\pi x^2 \]
\[ \Rightarrow \frac{∆ y}{y} = \frac{2\pi x^2}{y}dx = \frac{3}{x} \times \lambda x\]
\[ \Rightarrow \frac{∆ y}{y} = 3\lambda\%\]
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