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Question
Write the isomers of the compound having the formula C4H9Br.
Solution
C4H9Br is a saturated compound because its parent hydrocarbon is C4H10. Its isomers are as follows –
(i) \[\ce{\underset{1-Bromobutane}{CH3 - CH2 - CH2 - CH2 - Br}}\]
(ii) \[\begin{array}{cc}
\phantom{.......}\ce{Br}\\
\phantom{.....}|\\
\ce{\underset{2-Bromobutane}{CH3-CH2-CH-CH3}}
\end{array}\]
(iii) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{\underset{1-Bromo-2-Methylpropane}{CH3-CH-CH2Br}}
\end{array}\]
(iv) \[\begin{array}{cc}
\ce{CH3}\\
|\phantom{...}\\
\ce{CH3 - C - Br}\phantom{.....}\\
|\phantom{...}\\
\phantom{.}\ce{\underset{2-Bromo-2-Methylpropane}{CH3}}
\end{array}\]
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