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प्रश्न
`∫_4^9 1/sqrtxdx=`_____
(A) 1
(B) –2
(C) 2
(D) –1
उत्तर
Let `I=∫_4^9 1/sqrtxdx`
`=∫_4^9 x^-(1/2)dx`
`=[x^(1/2)/(1/2)]_4^9=2[sqrtx]_4^9`
`=2(sqrt9-sqrt4)`
`=2(3-2)`
`therefore I=2`
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