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प्रश्न
A particle in S.H.M. has a period of 2 seconds and amplitude of 10 cm. Calculate the acceleration when it is at 4 cm from its positive extreme position.
उत्तर
A particle in SHM has a period of 2 seconds and an amplitude of 10 cm. When it is at 4 cm from its positive extreme position, the displacement (x) of the particle is 10 - 4 = 6 cm.
Acceleration = ω2.x (in magnitude)
`=((2pi)/T)^2x`
`=(4pi^2)/(2)^2xx 6`
= 59.16 cm/s2
Thus, the acceleration of the particle at 4 cm from its positive extreme position is 59.16 cm/s2.
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