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प्रश्न
Choose the correct alternative:
`int(1 - x)^(-2) dx` = ______.
विकल्प
`(1 - x)^(-1) + c`
`(1 + x)^(-1) + c`
`(1 - x)^(-1) - 1 + c`
`(1 - x)^(-1) + 1 + c`
उत्तर
`int(1 - x)^(-2)dx` = `bb(underline((1 - x)^(-1) + c))`.
Explanation:
`int(1 - x)^(-2)dx = ((1 - x)^(-2 + 1))/((-2 + 1)).d/dx(1 - x) + c`
= `(1 - x)^-1/((-1)).(0 - 1) + c`
= (1 – x)–1 + c
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