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प्रश्न
Evaluate `cos[sin^-1 1/4 + sec^-1 4/3]`
उत्तर
`cos[sin^-1 1/4 + sec^-1 4/3] = cos[sin^-1 1/4 + cos^-1 3/4]`
= `cos(sin^-1 1/4) cos(cos^-1 3/4) - sin(sin^-1 1/4) sin(cos^-1 3/4)`
= `3/4 sqrt(1 - (1/4)^2) - 1/4 sqrt(1 - (3/4)^2`
= `3/4 sqrt(15)/4 - 1/4 sqrt(7)/4`
= `(3sqrt(15) - sqrt(7))/6`
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