Advertisements
Advertisements
प्रश्न
Evaluate the following: `(5cot5° cot15° cot25° cot35° cot45°)/(7tan45° tan55° tan65° tan75° tan85°) + (2"cosec"12° "cosec"24° cos78° cos66°)/(7sin14° sin23° sec76° sec67°)`
उत्तर
`(5cot5° cot15° cot25° cot35° cot45°)/(7tan45° tan55° tan65° tan75° tan85°) + (2"cosec"12° "cosec"24° cos78° cos66°)/(7sin14° sin23° sec76° sec67°)`
= `(5cot(90° - 85°) cot(90° - 75°) cot(90° - 65°) cot(90° - 55°) xx 1)/(7 xx 1xx tan55° tan65° tan75° tan85°) + (2"cosec"(90° - 78°) "cosec"(90° - 66°) cos78° cos66°)/(7sin(90° - 76°) sin(90° - 67°) sec76° sec67°)`
= `(5tan85° tan75° tan65° tan55°)/(7 xx tan55° tan65° tan75° tan85°) + (2sec78° sec66° xx 1/(sec78°) xx 1/(sec66°))/(7cos76° cos67° xx 1/(cos76°) xx 1/(cos67°)`
= `(5)/(7) + (2)/(7)`
= `(7)/(7)`
= 1.
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if sec 2A = 2
Find the value of 'A', if 2cos 3A = 1
Find the value of 'A', if `sqrt(3)cot"A"` = 1
If sin α + cosβ = 1 and α= 90°, find the value of 'β'.
If tanθ= cotθ and 0°≤ θ ≤ 90°, find the value of 'θ'.
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Evaluate the following: `(3sin37°)/(cos53°) - (5"cosec"39°)/(sec51°) + (4tan23° tan37° tan67° tan53°)/(cos17° cos67° "cosec"73° "cosec"23°)`
If cosθ = sin60° and θ is an acute angle find the value of 1- 2 sin2θ
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
Prove the following: tanθ tan(90° - θ) = cotθ cot(90° - θ)