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प्रश्न
Find `"dy"/"dx"`, if : x = sinθ, y = tanθ
उत्तर
x = sinθ, y = tanθ
Differentiating x and y w.r.t. x, we get
`"dx"/"dθ" = "d"/"dθ"(sinθ)` = cosθ
and
`"dy"/"dθ" = "d"/"dθ"(tanθ)` = sec2θ
`"dy"/"dx" = (("dy"/"dθ"))/(("dx"/"dθ")`
= `sec^2θ/cosθ`
= sec3θ.
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