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Find the area of a quadrant of a circle whose circumference is 22 cm. [Use π=227] - Mathematics

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प्रश्न

Find the area of a quadrant of a circle whose circumference is 22 cm. [Use `pi = 22/7`]

योग

उत्तर

Let the radius of the circle be r.

Circumference = 22 cm

2πr = 22

`2 xx 22/7 xx r = 22`

`r = 22 xx7/22 xx 1/2 `

= `r = 7/2`

Here θ = 90°

∴ Area of the `(1/4)^(th)` quadrant of the circle = `theta/(360°) xx pir^2`

`= (90°)/(360°) xx 22/7 xx (7/2)^2`cm2

`= 1/4 xx 22/7 xx 7/2 xx 7/2` cm

`= 77/8` cm2

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अध्याय 12: Areas Related to Circles - Exercise 12.2 [पृष्ठ २३०]

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एनसीईआरटी Mathematics [English] Class 10
अध्याय 12 Areas Related to Circles
Exercise 12.2 | Q 2 | पृष्ठ २३०

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