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Question
Find the area of a quadrant of a circle whose circumference is 22 cm. [Use `pi = 22/7`]
Solution
Let the radius of the circle be r.
Circumference = 22 cm
2πr = 22
`2 xx 22/7 xx r = 22`
`r = 22 xx7/22 xx 1/2 `
= `r = 7/2`
Here θ = 90°
∴ Area of the `(1/4)^(th)` quadrant of the circle = `theta/(360°) xx pir^2`
`= (90°)/(360°) xx 22/7 xx (7/2)^2`cm2
`= 1/4 xx 22/7 xx 7/2 xx 7/2` cm2
`= 77/8` cm2
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