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Question
Area of a sector of angle p (in degrees) of a circle with radius R is ______.
Options
`p/180 xx 2piR`
`p/180 xxpiR^2`
`p/360 xx 2piR`
`p/720 xx 2 pi R^2`
Solution
Area of a sector of angle p (in degrees) of a circle with radius R is `bbunderline(P/720 xx 2 pi R^2)`.
Explanation:
We know that area of sector of angle θ = `theta/360^@ xx piR^2`
Area of sector of angle P = `p/360^@(piR^2)`
`= theta/(360°) xx piR^2`
`= p/(360°) xx piR^2`
`= 2/2 xx (p/(360°) xx piR^2)`
Hence, `p/(720°) xx 2 pi R^2` is the correct answer.
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