हिंदी

Find the area of the region bounded by the curve ay2 = x3, the y-axis and the lines y = a and y = 2a. - Mathematics

Advertisements
Advertisements

प्रश्न

Find the area of the region bounded by the curve ay2 = x3, the y-axis and the lines y = a and y = 2a.

योग

उत्तर

We have

Area BMNC = `int_"a"^(2"a") x"d"y`

= `int_"a"^(2"a") "a"^(1/3) y^(2/3) "d"y`

= `(3"a"^(1/3))/5|y^(5/3)|_"a"^(2"a")`

= `(3"a"^(1/3))/5|(2"a")^(5/3) - "a"^(5/3)|`

= `3/5 "a"^(1/3) "a"^(5/3) |(2)^(5/3) - 1|`

= `3/5 "a"^2 |2.2^(2/3) - 1|` sq.units

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Application Of Integrals - Solved Examples [पृष्ठ १७१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 8 Application Of Integrals
Solved Examples | Q 2 | पृष्ठ १७१

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Using integration, find the area of the region bounded by the lines y = 2 + x, y = 2 – x and x = 2.


Find the area of the region lying in the first quandrant bounded by the curve y2= 4x, X axis and the lines x = 1, x = 4


Sketch the graph of y = |x + 4|. Using integration, find the area of the region bounded by the curve y = |x + 4| and x = –6 and x = 0.


Using integration, find the area of the region bounded by the line y − 1 = x, the x − axis and the ordinates x= −2 and x = 3.


Using integration, find the area of the region bounded by the following curves, after making a rough sketch: y = 1 + | x + 1 |, x = −2, x = 3, y = 0.


Sketch the graph y = | x + 1 |. Evaluate\[\int\limits_{- 4}^2 \left| x + 1 \right| dx\]. What does the value of this integral represent on the graph?


Draw a rough sketch of the curve \[y = \frac{x}{\pi} + 2 \sin^2 x\] and find the area between the x-axis, the curve and the ordinates x = 0 and x = π.


Find the area bounded by the curve y = cos x, x-axis and the ordinates x = 0 and x = 2π.


Find the area of the region bounded by the curve \[x = a t^2 , y = 2\text{ at }\]between the ordinates corresponding t = 1 and t = 2.


Draw a rough sketch and find the area of the region bounded by the two parabolas y2 = 4x and x2 = 4y by using methods of integration.


Find the area, lying above x-axis and included between the circle x2 + y2 = 8x and the parabola y2 = 4x.


Find the area of the region bounded by \[y = \sqrt{x}\] and y = x.


Find the area of the region bounded by the parabola y2 = 2x + 1 and the line x − y − 1 = 0.


Using integration, find the area of the triangle ABC coordinates of whose vertices are A (4, 1), B (6, 6) and C (8, 4).


Using integration find the area of the region:
\[\left\{ \left( x, y \right) : \left| x - 1 \right| \leq y \leq \sqrt{5 - x^2} \right\}\]


Find the area of the region enclosed by the parabola x2 = y and the line y = x + 2.


Find the area bounded by the lines y = 4x + 5, y = 5 − x and 4y = x + 5.


If the area above the x-axis, bounded by the curves y = 2kx and x = 0, and x = 2 is \[\frac{3}{\log_e 2}\], then the value of k is __________ .


The area bounded by the curve y = loge x and x-axis and the straight line x = e is ___________ .


The area bounded by the curves y = sin x between the ordinates x = 0, x = π and the x-axis is _____________ .


The area bounded by the parabola y2 = 4ax and x2 = 4ay is ___________ .


The closed area made by the parabola y = 2x2 and y = x2 + 4 is __________ .


Find the area of the region bounded by the parabolas y2 = 6x and x2 = 6y.


Find the area of the region above the x-axis, included between the parabola y2 = ax and the circle x2 + y2 = 2ax.


Find the area of the region bounded by y = `sqrt(x)` and y = x.


Find the area of the region bounded by the curve y2 = 2x and x2 + y2 = 4x.


The area of the region enclosed by the parabola x2 = y, the line y = x + 2 and the x-axis, is 


The area bounded by the curve `y = x|x|`, `x`-axis and the ordinate `x` = – 1 and `x` = 1 is given by


The area of the region S = {(x, y): 3x2 ≤ 4y ≤ 6x + 24} is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×