Advertisements
Advertisements
प्रश्न
Find the area of the region bounded by the curves y2 = 9x, y = 3x
उत्तर
We have, y2 = 9x, y = 3x
Solving the two equations,
We have (3x)2 = 9x
⇒ 9x2 – 9x = 0
⇒ 9x(x – 1) = 0
∴ x = 0, 1
Area of the shaded region
= ar (region OAB) – ar (ΔOAB)
= `- int_0^1 y_1 * "d"x`
= `int_0^1 sqrt(9x) "d"x - int_0^1 3x "d"x`
= `3 int_0^1 sqrt(x) "d"x - 3 int_0^1 x "d"x`
= `3 xx 2/3 [x^(3/2)]_0^1 - 3[x^2/2]_0^1`
= `2[(1)^(3/2) - 0] - 3/2 [(1)^2 - 0]`
= `2(1) - 3/2 (1)`
= `2 - 3/2`
= `1/2` sq.units
Hence, the required area = `1/2` sq.units
APPEARS IN
संबंधित प्रश्न
Find the area bounded by the curve y2 = 4ax, x-axis and the lines x = 0 and x = a.
Find the area of the region bounded by the curve x2 = 16y, lines y = 2, y = 6 and Y-axis lying in the first quadrant.
Using integration, find the area of the region bounded by the line 2y = 5x + 7, x-axis and the lines x = 2 and x = 8.
Sketch the graph y = | x + 3 |. Evaluate \[\int\limits_{- 6}^0 \left| x + 3 \right| dx\]. What does this integral represent on the graph?
Draw a rough sketch of the curve y = \[\frac{\pi}{2} + 2 \sin^2 x\] and find the area between x-axis, the curve and the ordinates x = 0, x = π.
Find the area of the region bounded by x2 + 16y = 0 and its latusrectum.
Using integration, find the area of the region bounded by the triangle whose vertices are (−1, 2), (1, 5) and (3, 4).
Using integration find the area of the region:
\[\left\{ \left( x, y \right) : \left| x - 1 \right| \leq y \leq \sqrt{5 - x^2} \right\}\]
Find the area of the region bounded by y = | x − 1 | and y = 1.
Find the area of the figure bounded by the curves y = | x − 1 | and y = 3 −| x |.
Find the area bounded by the parabola x = 8 + 2y − y2; the y-axis and the lines y = −1 and y = 3.
If the area above the x-axis, bounded by the curves y = 2kx and x = 0, and x = 2 is \[\frac{3}{\log_e 2}\], then the value of k is __________ .
Area of the region bounded by the curve y2 = 4x, y-axis and the line y = 3, is
Using the method of integration, find the area of the triangle ABC, coordinates of whose vertices area A(1, 2), B (2, 0) and C (4, 3).
Using integration, find the area of the region bounded by the parabola y2 = 4x and the circle 4x2 + 4y2 = 9.
Find the area of the region bounded by the parabola y2 = 2x and the straight line x – y = 4.
The area enclosed by the ellipse `x^2/"a"^2 + y^2/"b"^2` = 1 is equal to ______.
The area of the region bounded by the curve y = x2 and the line y = 16 ______.
Draw a rough sketch of the region {(x, y) : y2 ≤ 6ax and x 2 + y2 ≤ 16a2}. Also find the area of the region sketched using method of integration.
Find the area bounded by the lines y = 4x + 5, y = 5 – x and 4y = x + 5.
The area of the region bounded by the curve y = sinx between the ordinates x = 0, x = `pi/2` and the x-axis is ______.
If a and c are positive real numbers and the ellipse `x^2/(4c^2) + y^2/c^2` = 1 has four distinct points in common with the circle `x^2 + y^2 = 9a^2`, then
Find the area of the region bounded by the ellipse `x^2/4 + y^2/9` = 1.
The area bounded by the curve `y = x|x|`, `x`-axis and the ordinate `x` = – 1 and `x` = 1 is given by
Let T be the tangent to the ellipse E: x2 + 4y2 = 5 at the point P(1, 1). If the area of the region bounded by the tangent T, ellipse E, lines x = 1 and x = `sqrt(5)` is `sqrt(5)`α + β + γ `cos^-1(1/sqrt(5))`, then |α + β + γ| is equal to ______.
The area (in square units) of the region bounded by the curves y + 2x2 = 0 and y + 3x2 = 1, is equal to ______.
Using integration, find the area of the region bounded by line y = `sqrt(3)x`, the curve y = `sqrt(4 - x^2)` and Y-axis in first quadrant.
Sketch the region bounded by the lines 2x + y = 8, y = 2, y = 4 and the Y-axis. Hence, obtain its area using integration.
Evaluate:
`int_0^1x^2dx`
Hence find the area bounded by the curve, y = x |x| and the coordinates x = −1 and x = 1.