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From the rate expression for the following reaction, determine the order of reaction and the dimension of the rate constant. CHA3CHOA(g)⟶CHA4A(g)+COA(g) Rate = k [CH3CHO]3/2 - Chemistry

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प्रश्न

From the rate expression for the following reaction, determine the order of reaction and the dimension of the rate constant.

\[\ce{CH3CHO_{(g)} -> CH4_{(g)} + CO_{(g)}}\] Rate = k [CH3CHO]3/2

संख्यात्मक

उत्तर

Given rate = k [CH3CHO]3/2

Therefore, order of reaction = `3/2`

Dimension of k = `"Rate"/["CH"_3"CHO"]^(3/2)`

= `("mol L"^-1  "s"^(-1))/("mol L"^(-1))^(3/2)`

= `"L"^(1/2)  "mol"^(-1/2)  "s"^(-1)`

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अध्याय 4: Chemical Kinetics - Exercises [पृष्ठ ११७]

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एनसीईआरटी Chemistry [English] Class 12
अध्याय 4 Chemical Kinetics
Exercises | Q 1.3 | पृष्ठ ११७

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