Advertisements
Advertisements
प्रश्न
If 1176 = `2^axx3^bxx7^c,` find the values of a, b and c. Hence, compute the value of `2^axx3^bxx7^-c` as a fraction.
उत्तर
First find the prime factorisation of 1176.
It can be observed that 1176 can be written as `2^3xx3^1xx7^2`
`1176=2^a3^b7^c=2^3 3^1 7^2`
So, a = 3, b = 1 and c = 2.
Therefore, the value of `2^a xx3^bxx76-c` is `2^3xx3^1xx7^-2=8xx3xx1/49=24/49`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((4xx10^7)(6xx10^-5))/(8xx10^4)`
Simplify:
`root3((343)^-2)`
Find the value of x in the following:
`2^(x-7)xx5^(x-4)=1250`
Solve the following equation:
`sqrt(a/b)=(b/a)^(1-2x),` where a and b are distinct primes.
For any positive real number x, find the value of \[\left( \frac{x^a}{x^b} \right)^{a + b} \times \left( \frac{x^b}{x^c} \right)^{b + c} \times \left( \frac{x^c}{x^a} \right)^{c + a}\].
Which one of the following is not equal to \[\left( \sqrt[3]{8} \right)^{- 1/2} ?\]
`(2/3)^x (3/2)^(2x)=81/16 `then x =
If 102y = 25, then 10-y equals
If 10x = 64, what is the value of \[{10}^\frac{x}{2} + 1 ?\]
Find:-
`32^(1/5)`
