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If A and B are complementary angles, prove that: cot A cot B – sin A cos B – cos A sin B = 0 - Mathematics

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प्रश्न

If A and B are complementary angles, prove that:

cot A cot B – sin A cos B – cos A sin B = 0

योग

उत्तर

Since, A and B are complementary angles, A + B = 90°

cot A cot B – sin A cos B – cos A sin B

= cot A cot (90° – A) – sin A cos (90° – A) – cos A sin (90° – A)

= cot A tan A – sin A sin A – cos A cos A

= 1 – (sin2 A + cos2 A)

= 1 – 1

= 0

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अध्याय 21: Trigonometrical Identities - Exercise 21 (E) [पृष्ठ ३३२]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 21 Trigonometrical Identities
Exercise 21 (E) | Q 9.2 | पृष्ठ ३३२

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