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प्रश्न
If ax = by = cz and b2 = ac, prove that y = `(2xz)/(z + x)`
उत्तर
Let ax = by = cz = k
⇒ `"a" = "k"^(1/x), "b" = "k"^(1/y), "c" = "k"^(1/2)`
It is also given that b2 = ac
⇒ `"k"^(2/y) = "k"^(1/x) xx "k"^(1/2)`
⇒ `"k"^(2/y) = "k"^(1/x + 1/z)`
⇒ `(2)/y = (1)/x + (1)/z`
⇒ y = `(2zx)/(z + x)`.
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