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In Triangle Abc; ∠Abc = 90°, ∠Cab = X°, Tan X° = (3)/(4) and Bc = 15 Cm. Find the Measures of Ab and Ac - Mathematics

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प्रश्न

In triangle ABC; ∠ABC = 90°, ∠CAB = x°, tan x° = `(3)/(4)` and BC = 15 cm. Find the measures of AB and AC.

योग

उत्तर

Consider the figure:

tan x° = `(3)/(4)`

i.e. `"perpendicular"/"base" = "BC"/"AB" =(3)/(4)`

Therefore if length of base = 4x, length of perpendicular = 3x

Since
BC2 + AB2 = AC2  ...[Using Pythagoras Theorem]

(3x)2 + (4x)2 = AC2

AC2 = 9x2 + 16x2

AC2 = 25x2

AC = `sqrt(25x^2)`

∴ AC = 5x 

Now 
BC = 15

3x = 15

x = `15/3`

x = 5

Therefore

AB = 4x

= 4 × 5

= 20 cm

And
AC = 5x

= 5 × 5

= 25 cm

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अध्याय 22: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals] - Exercise 22 (B) [पृष्ठ २८६]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 22 Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
Exercise 22 (B) | Q 7 | पृष्ठ २८६
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