मराठी

All the Letters of the Word 'Eamcot' Are Arranged in Different Possible Ways. Find the Number of Arrangements in Which No Two Vowels Are Adjacent to Each Other. - Mathematics

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प्रश्न

All the letters of the word 'EAMCOT' are arranged in different possible ways. Find the number of arrangements in which no two vowels are adjacent to each other.

उत्तर

We note that, there are 3 consonants M, C, T and 3 vowels E, A, O.

Since, no two vowels have to be together, the possible choice for volwels are the blank spaces

\[_M_C_T_\]

These vowels can be arranged in 4P3 ways.
3 consonants can be arranged in 3! ways.

Hence, the required numbers of ways = 3! × 4P3 = 144 ways.

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Factorial N (N!) Permutations and Combinations
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पाठ 16: Permutations - Exercise 16.3 [पृष्ठ २९]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 16 Permutations
Exercise 16.3 | Q 32 | पृष्ठ २९

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