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Differentiate Sin(Log Sin X) ? - Mathematics

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प्रश्न

Differentiate sin(log sin x) ?

बेरीज

उत्तर

Let y = sin (log sin x)

Differentiate it with respect to x We get,

dydx=ddxsin(logsinx)

=cos(logsinx)ddx(logsinx)       [Using chain rule]

=cos(logsinx)×1sinxddxsinx         [Using chain rule]

=cos(logsinx)cosxsinx

=cos(logsinx)cotx

Hence, ddxsin(logsinx)=cos(logsinx)cotx

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पाठ 11: Differentiation - Exercise 11.02 [पृष्ठ ३७]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 11 Differentiation
Exercise 11.02 | Q 22 | पृष्ठ ३७

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