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Evaluate the following: 5cos260°+ 4sec230°-tan245°sin230°+ cos230° - Mathematics

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प्रश्न

Evaluate the following:

`(5cos^2 60° +  4sec^2 30° - tan^2 45°)/(sin^2 30° +  cos^2 30°)`

बेरीज

उत्तर

`(5cos^2 60° +  4sec^2 30° - tan^2 45°)/(sin^2 30°+  cos^2 30°)`

= `(5(1/2)^2 + 4(2/sqrt3)^2 - (1)^2)/((1/2)^2 + ((sqrt3)/2)^2)`

= `(5/4 + 16/3 - 1)/(1/4 + 3/4)`

= `(1/12(15 + 64 - 12))/((1  +  3)/4`

= `(1/12 xx67)/(4/4)`

= `67/12`

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पाठ 8: Introduction to Trigonometry - Exercise 8.2 [पृष्ठ १८७]

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एनसीईआरटी Mathematics [English] Class 10
पाठ 8 Introduction to Trigonometry
Exercise 8.2 | Q 1.5 | पृष्ठ १८७

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