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प्रश्न
Without using table, find the value of the following:
`(sin30° - sin90° + 2cos0°)/(tan30° tan60°)`
उत्तर
`(sin30° - sin90° + 2cos0°)/(tan30° tan60°)`
= `(1/2 - 1 + 2 xx 1)/(1/sqrt(3) xx sqrt(3))`
= `(1/2 - 1 + 2)/(1)`
= `(1)/(2) - 1 + 2`
= `(1)/(2) + 1`
= `(3)/(2)`
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