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Without using tables, find the value of the following: sin 30 ° sin 45 ° + tan 45 ° sec 60 ° − sin 60 ° cot 45 ° − cos 30 ° sin 90 ° - Mathematics

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प्रश्न

Without using tables, find the value of the following: `(sin30°)/(sin45°) + (tan45°)/(sec60°) - (sin60°)/(cot45°) - (cos30°)/(sin90°)`

बेरीज

उत्तर

`(sin30°)/(sin45°) + (tan45°)/(sec60°) - (sin60°)/(cot45°) - (cos30°)/(sin90°)`

= `(1/2)/(1/sqrt(2)) + (1)/(2) - (sqrt(3)/2)/(1) - (sqrt(3)/2)/(1)`

= `sqrt(2)/(2) + (1)/(2) - sqrt(3)/(2) - sqrt(3)/(2)`

= `(sqrt(2) + 1 - 2sqrt(3))/(2)`.

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पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.1

APPEARS IN

फ्रँक Mathematics [English] Class 9 ICSE
पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.1 | Q 2.2

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