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Without using tables, evaluate the following sec45° sin45° - sin30° sec60°. - Mathematics

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प्रश्न

Without using tables, evaluate the following sec45° sin45° - sin30° sec60°.

बेरीज

उत्तर

sec45° sin45° -  sin30° sec60°.

cos45° = `(1)/sqrt(2)`

⇒ sec45° = `sqrt(2)`

sin45° = `(1)/sqrt(2)`

sin30° = `(1)/(2)`

cos60° = `(1)/(2)`

⇒ sec60° = 2
sec45° sin45° -  sin30° sec60°

= `sqrt(2) xx (1)/sqrt(2) - (1)/sqrt(2) xx 2`
= 1 - 1
= 0.

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पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.1

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फ्रँक Mathematics [English] Class 9 ICSE
पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.1 | Q 1.03

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