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प्रश्न
Prove that:
3 cosec2 60° - 2 cot2 30° + sec2 45° = 0
उत्तर
LHS =3 cosec260° – 2 cot230° + sec245°
=`3(2/sqrt3)^2 – 2(sqrt3)^2 + (sqrt2)^2`
= `3xx4/3-2xx3+2`
= 4 – 6 + 2
= 0
= RHS
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