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Without using tables, evaluate the following: sin230° cos245° + 4tan230° + sin290° + cos20° - Mathematics

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प्रश्न

Without using tables, evaluate the following: sin230° cos245° + 4tan230° + sin290° + cos2

बेरीज

उत्तर

sin230° cos245° + 4tan230° + sin290° + cos2

sin30° = `(1)/(2)`

cos45° = `(1)/sqrt(2)`

tan30° = `(1)/sqrt(3)`

sin90° = 1
cos0° = 1
sin230° cos245° + 4tan230° + sin290° + cos2

= `(1/2)^2 (1/sqrt(2))^2 + 4(1/sqrt(3))^2 + 1 + 1`

= `(1)/(4) xx (1)/(2) + (4)/(3) + 2`

= `(1)/(8) + (4)/(3) + 2`

= `(3 + 32 + 48)/(24)`

= `(83)/(24)`.

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पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.1

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फ्रँक Mathematics [English] Class 9 ICSE
पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.1 | Q 1.06

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