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प्रश्न
f(x) = `{{:(|x - "a"| sin 1/(x - "a")",", "if" x ≠ 0),(0",", "if" x = "a"):}` at x = a
उत्तर
We have, f(x) = `{{:(|x - "a"| sin 1/(x - "a")",", "if" x ≠ 0),(0",", "if" x = "a"):}` at x = a
At x = a
L.H.L. = `lim_(x -> "a"^-) |x - "a"| sin 1/(x - "a")`
= `lim_("h" -> 0) |"a" - "h" - "a"| sin(1/("a" - "h" - "a"))`
= `lim_("h" -> 0) - "h" sin 1/"h"`
= 0 × [an oscillating number between –1 and 1] = 0
R.H.L. = `lim_(x -> "a"^+) |x - "a"|sin(1/(x - "a"))`
= `lim_("h" -> 0) |"a" + "h" - "a"| sin(1/("a" + "h" - "a"))`
= `lim_("h" -> 0) "h" sin 1/"h"`
= 0 × [an oscillating number between –1 and 1] = 0
Also f(a) = 0 ...(Given)
Thus L.H.L. = R.H.L. = f(a)
So, f(x) is continuous at x = a.
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