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प्रश्न
Find `dy/dx` in the following:
ax + by2 = cos y
उत्तर
Since ax + by2 = cos y
Differentiating both sides with respect to x,
`=>a d/dx (x) + b d/dx (y2) = d/dx(cos y)`
`=> a xx 1 + b * 2y dy/dx = - sin y dy/dx`
`=> a + 2by dy/dx + sin y dy/dx = 0`
`=> a + dy/dx (2by +sin y) = 0`
`=> dy/dx (2by + sin y) = - a`
`therefore dy/dx = (-a)/(2by + sin y)`
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