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Find dydx in the following: sin2 y + cos xy = k - Mathematics

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प्रश्न

Find `dy/dx` in the following:

sin2 y + cos xy = k

बेरीज

उत्तर

Since, sin2 y + cos xy = k

Differentiating both sides with respect to x,

`d/dx (sin^2 y) + d/dx (cos xy) = d/dx (k)`

`=> 2 sin y cos y dy/dx + (- sin xy) d/dx (xy) = 0`

`=> 2 sin y cos y dy/dx - sin xy [x dy/dx + y d/dx (x)] = 0`

`=> 2 sin y cos y dy/dx - x sin xy dy/dx - y sin xy = 0`

`=> sin  2y - x sin xy dy/dx - y sin xy = 0`

`=> dy/dx (sin  2y - x sin xy) = y sin xy`

`dy/dx = (y sin xy)/((sin  2y - x sin xy))`

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पाठ 5: Continuity and Differentiability - Exercise 5.3 [पृष्ठ १६९]

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एनसीईआरटी Mathematics [English] Class 12
पाठ 5 Continuity and Differentiability
Exercise 5.3 | Q 7 | पृष्ठ १६९

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