मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the domain and range of the following function. f(x) = (x-2)(5-x) - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Find the domain and range of the following function.

f(x) = `sqrt((x - 2)(5 - x)`

बेरीज

उत्तर

f(x) = `sqrt((x - 2)(5 - x)`

For f to be defined,

(x – 2) (5 – x) ≥ 0

∴(x – 2) (x – 5) ≤ 0

∴ 2 ≤ x ≤ 5   ...`[("The solution of" (x - "a") (x - "b") ≤ 0),("is"  "a" ≤ x ≤ "b"","  "for"  "a" < "b")]`

Domain = [2, 5]

(x – 2) (5 – x) = – x2 + 7x – 10

= `-(x - 7/2)^2 + 49/4 - 10`

= `9/4 - (x - 7/2)^2 ≤ 9/4`

∴ `sqrt((x - 2)(5 - x)) ≤ sqrt(9/4) ≤ 3/2`

∴ Range of f = `[0, 3/2]`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Functions - Exercise 6.1 [पृष्ठ ११८]

APPEARS IN

संबंधित प्रश्‍न

Let A = {−2, −1, 0, 1, 2} and f : A → Z be a function defined by f(x) = x2 − 2x − 3. Find:

(b) pre-images of 6, −3 and 5.

 

Let f : R → R and g : C → C be two functions defined as f(x) = x2 and g(x) = x2. Are they equal functions?


fgh are three function defined from R to R as follow:

(ii) g(x) = sin x

Find the range of function.


et A = (12, 13, 14, 15, 16, 17) and f : A → Z be a function given by
f(x) = highest prime factor of x.
Find range of f.


The function f is defined by \[f\left( x \right) = \begin{cases}x^2 , & 0 \leq x \leq 3 \\ 3x, & 3 \leq x \leq 10\end{cases}\]

The relation g is defined by \[g\left( x \right) = \begin{cases}x^2 , & 0 \leq x \leq 2 \\ 3x, & 2 \leq x \leq 10\end{cases}\]

Show that f is a function and g is not a function.


Let f and g be two real functions defined by \[f\left( x \right) = \sqrt{x + 1}\] and \[g\left( x \right) = \sqrt{9 - x^2}\] . Then, describe function: 

(iv) \[\frac{f}{g}\]

 

Let f and g be two real functions defined by \[f\left( x \right) = \sqrt{x + 1}\] and \[g\left( x \right) = \sqrt{9 - x^2}\] . Then, describe function: 

(vi)  \[2f - \sqrt{5} g\]

 

If f(x) = loge (1 − x) and g(x) = [x], then determine function:

(iii) \[\frac{f}{g}\]

 

If f(x) = loge (1 − x) and g(x) = [x], then determine function:

(iv) \[\frac{g}{f}\] Also, find (f + g) (−1), (fg) (0),

\[\left( \frac{f}{g} \right) \left( \frac{1}{2} \right), \left( \frac{g}{f} \right) \left( \frac{1}{2} \right)\]
 
 

If f is a real function satisfying \[f\left( x + \frac{1}{x} \right) = x^2 + \frac{1}{x^2}\]

for all x ∈ R − {0}, then write the expression for f(x).

 
 

Let  \[f\left( x \right) = \frac{\alpha x}{x + 1}, x \neq - 1\] . Then write the value of α satisfying f(f(x)) = x for all x ≠ −1.

 

 


Write the domain and range of the function  \[f\left( x \right) = \frac{x - 2}{2 - x}\] .

 

Let f and g be two functions given by

f = {(2, 4), (5, 6), (8, −1), (10, −3)} and g = {(2, 5), (7, 1), (8, 4), (10, 13), (11, −5)}.

Find the domain of f + g


If f : Q → Q is defined as f(x) = x2, then f−1 (9) is equal to


Let f(x) = |x − 1|. Then,


If \[f\left( x \right) = \log \left( \frac{1 + x}{1 - x} \right)\] , then \[f\left( \frac{2x}{1 + x^2} \right)\]  is equal to

 

 


If f(x) = cos (loge x), then \[f\left( \frac{1}{x} \right)f\left( \frac{1}{y} \right) - \frac{1}{2}\left\{ f\left( xy \right) + f\left( \frac{x}{y} \right) \right\}\] is equal to

 

If : [−2, 2] → R is defined by \[f\left( x \right) = \begin{cases}- 1, & \text{ for }  - 2 \leq x \leq 0 \\ x - 1, & \text{ for }   0 \leq x \leq 2\end{cases}\] , then
{x ∈ [−2, 2] : x ≤ 0 and f (|x|) = x} =

 

The domain of definition of  \[f\left( x \right) = \sqrt{\frac{x + 3}{\left( 2 - x \right) \left( x - 5 \right)}}\] is 

  

The domain of definition of  \[f\left( x \right) = \sqrt{4x - x^2}\] is 

 

The domain of the function \[f\left( x \right) = \sqrt{5 \left| x \right| - x^2 - 6}\] is

 

If f(m) = m2 − 3m + 1, find f(− x)


Check if the relation given by the equation represents y as function of x:

x2 − y = 25


Express the following logarithmic equation in exponential form

`log_5  1/25` = – 2


Solve for x.

log2 x + log4 x + log16 x = `21/4`


If f(x) = 3x + 5, g(x) = 6x − 1, then find (fg) (3)


The equation logx2 16 + log2x 64 = 3 has,


Answer the following:

A function f : R → R defined by f(x) = `(3x)/5 + 2`, x ∈ R. Show that f is one-one and onto. Hence find f–1


Answer the following:

Show that, `log ("a"^2/"bc") + log ("b"^2/"ca") + log ("c"^2/"ab")` = 0


Answer the following:

Without using log tables, prove that `2/5 < log_10 3 < 1/2`


Answer the following:

Find the domain of the following function.

f(x) = `sqrt(x - x^2) + sqrt(5 - x)`


Answer the following:

Find (f ° g) (x) and (g ° f) (x)

f(x) = `x/(x + 1)`, g(x) = `x/(1 - x)`


Given the function f: x → x2 – 5x + 6, evaluate f(2a)


If f(x) = `1/sqrt(4 - 3x)`, then dom(f) = ______..


Find the range of the following functions given by f(x) = |x − 3|


If f(x) = y = `(ax - b)/(cx - a)`, then prove that f(y) = x.


The domain and range of the real function f defined by f(x) = `(4 - x)/(x - 4)` is given by ______.


Which of the following functions is NOT one-one?


If f : R – {2} `rightarrow` R i s a function defined by f(x) = `(x^2 - 4)/(x - 2)`, then its range is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×