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प्रश्न
For the principal value, evaluate the following:
`cosec^-1(2tan (11pi)/6)`
उत्तर
`cosec^-1(2tan (11pi)/6)=cosec^-1[2xx(-1/sqrt3)]`
`=cosec^-1[-2/sqrt3]`
`=cosec^-1[cosec(-pi/3)]`
`=-pi/3`
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